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2x^2-30x+88=0
a = 2; b = -30; c = +88;
Δ = b2-4ac
Δ = -302-4·2·88
Δ = 196
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{196}=14$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-14}{2*2}=\frac{16}{4} =4 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+14}{2*2}=\frac{44}{4} =11 $
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